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数据挖掘之Apriori算法详解和Python实现代码分享(2)

时间:2014-11-08 02:34来源:网络整理 作者:网络 点击:
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def find_item_name(self): "根据第一行抽取item_name" with open(self.filename, 'r') as F: for index,line in enumerate(F.readlines()): if index == 0: self.item_name = self.deal_line(line) break de

    def find_item_name(self):
        "根据第一行抽取item_name"
        with open(self.filename, 'r') as F:
            for index,line in enumerate(F.readlines()):
                if index == 0:
                    self.item_name = self.deal_line(line)
                    break

    def sut(self, location):
        """
        输入[[1,2,3],[2,3,4],[1,3,5]...]
        输出每个位置集的support [123,435,234...]
        """
        with open(self.filename, 'r') as F:
            support = [0] * len(location)
            for index,line in enumerate(F.readlines()):
                if index == 0: continue
                # 提取每信息
                item_line = self.deal_line(line)
                for index_num,i in enumerate(location):
                    flag = 0
                    for j in i:
                        if item_line[j] != 'T':
                            flag = 1
                            break
                    if not flag:
                        support[index_num] += 1
            self.line_num = index # 一共多少行,出去第一行的item_name
        return support

    def select(self, c):
        "返回位置"
        stack = []
        for i in self.location:
            for j in self.num:
                if j in i:
                    if len(i) == c:
                        stack.append(i)
                else:
                    stack.append([j] + i)
        # 多重列表去重
        import itertools
        s = sorted([sorted(i) for i in stack])
        location = list(s for s,_ in itertools.groupby(s))
        return location

    def del_location(self, support, location):
        "清除不满足条件的候选集"
        # 小于最小支持度的剔除
        for index,i in enumerate(support):
            if i < self.line_num * self.min_support / 100:
                support[index] = 0
        # apriori第二条规则,剔除
        for index,j in enumerate(location):
            sub_location = [j[:index_loc] + j[index_loc+1:]for index_loc in range(len(j))]
            flag = 0
            for k in sub_location:
                if k not in self.location:
                    flag = 1
                    break
            if flag:
                support[index] = 0
        # 删除没用的位置
        location = [i for i,j in zip(location,support) if j != 0]
        support = [i for i in support if i != 0]
        return support, location

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