python使用递归解决全排列数字示例
有1,2,3,4这4个数字，能组成多少个互不相同且无重复数字的三位数,下面是二种解决示例,需要的朋友可以参考下
第一种方法：递归
代码如下:
def perms(elements):
if len(elements) <=1:
yield elements
else:
for perm in perms(elements[1:]):
for i in range(len(elements)):
yield perm[:i] + elements[0:1] + perm[i:]
for item in list(perms([1, 2, 3,4])):
print item
结果
代码如下:
[1, 2, 3, 4]
[2, 1, 3, 4]
[2, 3, 1, 4]
[2, 3, 4, 1]
[1, 3, 2, 4]
[3, 1, 2, 4]
[3, 2, 1, 4]
[3, 2, 4, 1]
[1, 3, 4, 2]
[3, 1, 4, 2]
[3, 4, 1, 2]
[3, 4, 2, 1]
[1, 2, 4, 3]
[2, 1, 4, 3]
[2, 4, 1, 3]
[2, 4, 3, 1]
[1, 4, 2, 3]
[4, 1, 2, 3]
[4, 2, 1, 3]
[4, 2, 3, 1]
[1, 4, 3, 2]
[4, 1, 3, 2]
[4, 3, 1, 2]
[4, 3, 2, 1]
第二种方法：python标准库
代码如下:
import itertools
print list(itertools.permutations([1, 2, 3,4],3))
源代码如下：
代码如下:
#coding:utf-8
import itertools
print list(itertools.permutations([1, 2, 3,4],3))
def perms(elements):
if len(elements) <=1:
yield elements
else:
for perm in perms(elements[1:]):
for i in range(len(elements)):
yield perm[:i] + elements[0:1] + perm[i:]
for item in list(perms([1, 2, 3,4])):
print item
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