PHP subistr 截取字符串无码
PHP subistr 截取字符串无码 更新时间:20120102**[PHP]代码**[代码片段(48行)]
更新时间:20120102
[PHP]代码
<?php /** * [WebodMin] (C)2010-2099 Blank Inc. * This is NOT a freeware, use is subject to license terms * **/ function subistr($string, $length, $dot = ' ...') { global $charset; if(strlen($string) <= $length) { return $string; } $s = ''; if(strtolower($charset) == 'utf-8') { $n = $tn = $noc = 0; while($n < strlen($string)) { $t = ord($string[$n]); if($t == 9 || $t == 10 || (32 <= $t && $t <= 126)) { $tn = 1; $n++; $noc++; } elseif(194 <= $t && $t <= 223) { $tn = 2; $n += 2; $noc += 2; } elseif(224 <= $t && $t <= 239) { $tn = 3; $n += 3; $noc += 2; } elseif(240 <= $t && $t <= 247) { $tn = 4; $n += 4; $noc += 2; } elseif(248 <= $t && $t <= 251) { $tn = 5; $n += 5; $noc += 2; } elseif($t == 252 || $t == 253) { $tn = 6; $n += 6; $noc += 2; } else { $n++; } if($noc >= $length) { break; } } if($noc > $length) { $n -= $tn; } $s = substr($string, 0, $n); } else { for($i = 0; $i < $length; $i++) { $s .= ord($string[$i]) >= 127 ? $string[$i].$string[++$i] : $string[$i]; } } return $s.$dot; }
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